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Tug Boat “TB.LEVIATHAN” LINES PLAN BAB II PERHITUNGAN RENCANA GARIS (LINES PLAN) A. Perhitungan Dasar A.1. Panjang Garis Muat ( LWL ) LWL = Lpp + 2 % Lpp = 36.07 + ( 0.02 x 36.07 ) = 36.79 m A.2. Panjang Displacement untuk kapal Baling – baling ganda (L displ)
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   Tug Boat “TB.LEVIATHAN”  LINES PLAN Program Studi DIII Teknik Perkapalan II -1 Fakultas Teknik UNDIP YOSAFAT EDEN W. P. (L0G 007 046) BAB II PERHITUNGAN RENCANA GARIS (  LINES PLAN  ) A.   Perhitungan Dasar A.1.   Panjang Garis Muat ( LWL ) LWL = Lpp + 2 % Lpp = 36.07 + ( 0.02 x 36.07 ) = 36.79  m A.2.   Panjang  Displacement   untuk kapal Baling – baling ganda (L displ) L displ = LWL = 36.79 m  A.3.   Koefisien  Midship  ( Cm ) Menurut “ Van Lammerent  ” Cm = 0.91 - 0.1 x √ Cb = 0.91 - 0.1 x √ 0.52 = 0.828  ( 0.73 – 0.88 ) Memenuhi A.4.   Koefisien garis air ( Cw ) Menurut Troast   Cw = 025.0  cb  = 025.052.0    = 0.7  ( 0.70 – 0.81 ) Memenuhi A.5.   Koefisien Prismatik ( Cp ) Cp = Cb/Cm = 0.52 / 0.828 = 0.63  ( 0.61   0.70 ) Memenuhi A.6.   Luas Garis Air ( AWL ) AWL = LWL x B x Cw = 36.79 x 9 x 0.7   Tug Boat “TB.LEVIATHAN”  LINES PLAN Program Studi DIII Teknik Perkapalan II -2 Fakultas Teknik UNDIP YOSAFAT EDEN W. P. (L0G 007 046) = 231.78 m 2  A.7.   Luas  Midship  ( Am ) Am = B x T x Cm = 9 x 3.94 x 0.828 = 29.36  m 2  A.8.   Volume    Displacement   V displ = Lpp x B x T x Cb = 36.07 x 9 x 3.94x 0.52 = 665.1  m³ A.9.    Displacement   D = V displ x   x c Dimana :    = 1.025 Berat jenis air laut c = 1.004 Koefisient Pengelasan D = 665.1 x 1.025 x 1.004 = 684.45  Ton A.10.   Koefisien Prismatik  Displacement   ( Cp displ ) Cp Displ = ( Lpp / L displ ) x Cp = ( 36.07 / 36.79 ) x 0.63 = 0.62   Tug Boat “TB.LEVIATHAN”  LINES PLAN Program Studi DIII Teknik Perkapalan II -3 Fakultas Teknik UNDIP YOSAFAT EDEN W. P. (L0G 007 046) B.   Menentukan Letak Titik LCB B.1.   Dengan menggunakan Cp displacement   pada grafik NSP pada Cp displ = 0,62 didapat letak titik LCB (  Longitudinal centre of Bouyancy ) = 0,625 % x L displ, dimana L displ = 36.79 m Cp Displ = ( Lpp / L displ ) x Cp = ( 36.07 / 36.79 ) x 0.63 = 0.62 B.1.1.   Letak LCB Displ Menurut Grafik NSP LCB Displ = 0.625 % x L displ = 0.00625 x 36.79 = 0.23  m ( Dibelakang   L displ ) B.1.2.   Jarak  Midship  (   ) L displacement   ke FP   Displ = 0.5 x L displ = 0.5 x 36.79 = 18.395  m B.1.3.   Jarak  Midship  (   ) Lpp ke FP   Lpp = 0.5 x Lpp = 0.5 x 36.07 = 18.035  m B.1.4.   Jarak antara midship  (   ) Displ dengan midship  (   ) Lpp =   Displ –   Lpp = 18.395 – 18.035 = 0.36  m B.1.5.   Jarak antara LCB terhadap (   ) Lpp = 0.23 – 0.36 = 0.59  m ( Dibelakang   Lpp ) B.2.   Menurut Diagram NSP Dengan Luas Tiap station     Tug Boat “TB.LEVIATHAN”  LINES PLAN Program Studi DIII Teknik Perkapalan II -4 Fakultas Teknik UNDIP YOSAFAT EDEN W. P. (L0G 007 046) Am = 29.36  m 2   No. Ord % % x Am Fs Hasil Fm Hasil AP 0.00 0.000 1 0.000 -10 0.00 1 0.09 2.6424 4 10.5696 -9 -95.1264 2 0.24 7.0464 2 14.0928 -8 -112.742 3 0.42 12.3312 4 49.3248 -7 -345.274 4 0.6 17.616 2 35.232 -6 -211.392 5 0.75 22.02 4 88.08 -5 -440.4 6 0.85 24.956 2 49.912 -4 -199.648 7 0.93 27.3048 4 109.2192 -3 -327.658 8 0.98 28.7728 2 57.5456 -2 -115.091 9 0.99 29.0664 4 116.2656 -1 -116.266 10 1.00 29.36 2 58.72 0 0.00 ∑ 2 = -1963.6 11 0.99 29.0664 4 116.2656 1 116.2656 12 0.97 28.4792 2 56.9584 2 113.9168 13 0.91 26.7176 4 106.8704 3 320.6112 14 0.83 24.3688 2 48.7376 4 194.9504 15 0.68 19.9648 4 79.8592 5 399.296 16 0.52 15.2672 2 30.5344 6 183.2064 17 0.35 10.276 4 41.104 7 287.728 18 0.20 5.872 2 11.744 8 93.952 19 0.07 2.0552 4 8.2208 9 73.9872 FP 0.00 0.000 1 0.000 10 0.00 ∑ 1  = 1089.256 ∑ 3  = 1783.914
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